3+4cos(2x)+cos(4x)=

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Solution for 3+4cos(2x)+cos(4x)= equation:


Simplifying
3 + 4cos(2x) + cos(4x) = 0

Remove parenthesis around (2x)
3 + 4cos * 2x + cos(4x) = 0

Reorder the terms for easier multiplication:
3 + 4 * 2cos * x + cos(4x) = 0

Multiply 4 * 2
3 + 8cos * x + cos(4x) = 0

Multiply cos * x
3 + 8cosx + cos(4x) = 0

Remove parenthesis around (4x)
3 + 8cosx + cos * 4x = 0

Reorder the terms for easier multiplication:
3 + 8cosx + 4cos * x = 0

Multiply cos * x
3 + 8cosx + 4cosx = 0

Combine like terms: 8cosx + 4cosx = 12cosx
3 + 12cosx = 0

Solving
3 + 12cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 12cosx = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 12cosx = 0 + -3
12cosx = 0 + -3

Combine like terms: 0 + -3 = -3
12cosx = -3

Divide each side by '12osx'.
c = -0.25o-1s-1x-1

Simplifying
c = -0.25o-1s-1x-1

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