3+4x-3x+12=4(x-6)

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Solution for 3+4x-3x+12=4(x-6) equation: 



3+4x-3x+12=4(x-6)

We move all terms to the left:

3+4x-3x+12-(4(x-6))=0

We add all the numbers together, and all the variables

x-(4(x-6))+15=0



We calculate terms in parentheses: -(4(x-6)), so:

4(x-6)

We multiply parentheses

4x-24

Back to the equation:

-(4x-24)



We get rid of parentheses

x-4x+24+15=0

We add all the numbers together, and all the variables

-3x+39=0

We move all terms containing x to the left, all other terms to the right

-3x=-39

x=-39/-3

x=+13

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