3+4y=(4+5y)-72

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Solution for 3+4y=(4+5y)-72 equation: 



3+4y=(4+5y)-72

We move all terms to the left:

3+4y-((4+5y)-72)=0

We add all the numbers together, and all the variables

4y-((5y+4)-72)+3=0



We calculate terms in parentheses: -((5y+4)-72), so:

(5y+4)-72

We get rid of parentheses

5y+4-72

We add all the numbers together, and all the variables

5y-68

Back to the equation:

-(5y-68)



We get rid of parentheses

4y-5y+68+3=0

We add all the numbers together, and all the variables

-1y+71=0

We move all terms containing y to the left, all other terms to the right

-y=-71

y=-71/-1

y=+71

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