3+5(3v-2)=-4(3v-2)+9v

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Solution for 3+5(3v-2)=-4(3v-2)+9v equation: 



3+5(3v-2)=-4(3v-2)+9v

We move all terms to the left:

3+5(3v-2)-(-4(3v-2)+9v)=0

We multiply parentheses

15v-(-4(3v-2)+9v)-10+3=0



We calculate terms in parentheses: -(-4(3v-2)+9v), so:

-4(3v-2)+9v

We add all the numbers together, and all the variables

9v-4(3v-2)

We multiply parentheses

9v-12v+8

We add all the numbers together, and all the variables

-3v+8

Back to the equation:

-(-3v+8)



We add all the numbers together, and all the variables

15v-(-3v+8)-7=0

We get rid of parentheses

15v+3v-8-7=0

We add all the numbers together, and all the variables

18v-15=0

We move all terms containing v to the left, all other terms to the right

18v=15

v=15/18

v=5/6

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