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3+5(x-6)=2-3(x-1)
We move all terms to the left:
3+5(x-6)-(2-3(x-1))=0
We multiply parentheses
5x-(2-3(x-1))-30+3=0
We calculate terms in parentheses: -(2-3(x-1)), so:We add all the numbers together, and all the variables
2-3(x-1)
determiningTheFunctionDomain -3(x-1)+2
We multiply parentheses
-3x+3+2
We add all the numbers together, and all the variables
-3x+5
Back to the equation:
-(-3x+5)
5x-(-3x+5)-27=0
We get rid of parentheses
5x+3x-5-27=0
We add all the numbers together, and all the variables
8x-32=0
We move all terms containing x to the left, all other terms to the right
8x=32
x=32/8
x=4
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