3+5/7z=29

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Solution for 3+5/7z=29 equation: 



3+5/7z=29

We move all terms to the left:

3+5/7z-(29)=0



Domain of the equation: 7z!=0

z!=0/7

z!=0

z∈R



We add all the numbers together, and all the variables

5/7z-26=0

We multiply all the terms by the denominator


-26*7z+5=0

Wy multiply elements

-182z+5=0

We move all terms containing z to the left, all other terms to the right

-182z=-5

z=-5/-182

z=5/182

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