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3+5x=4(x+2)6x
We move all terms to the left:
3+5x-(4(x+2)6x)=0
We calculate terms in parentheses: -(4(x+2)6x), so:We get rid of parentheses
4(x+2)6x
We multiply parentheses
24x^2+48x
Back to the equation:
-(24x^2+48x)
-24x^2+5x-48x+3=0
We add all the numbers together, and all the variables
-24x^2-43x+3=0
a = -24; b = -43; c = +3;
Δ = b2-4ac
Δ = -432-4·(-24)·3
Δ = 2137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{2137}}{2*-24}=\frac{43-\sqrt{2137}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{2137}}{2*-24}=\frac{43+\sqrt{2137}}{-48} $
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