3+6s=(s-3)+19

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Solution for 3+6s=(s-3)+19 equation: 



3+6s=(s-3)+19

We move all terms to the left:

3+6s-((s-3)+19)=0



We calculate terms in parentheses: -((s-3)+19), so:

(s-3)+19

We get rid of parentheses

s-3+19

We add all the numbers together, and all the variables

s+16

Back to the equation:

-(s+16)



We get rid of parentheses

6s-s-16+3=0

We add all the numbers together, and all the variables

5s-13=0

We move all terms containing s to the left, all other terms to the right

5s=13

s=13/5

s=2+3/5

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