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3+7(2x-5)+x=128-5x
We move all terms to the left:
3+7(2x-5)+x-(128-5x)=0
We add all the numbers together, and all the variables
7(2x-5)+x-(-5x+128)+3=0
We add all the numbers together, and all the variables
x+7(2x-5)-(-5x+128)+3=0
We multiply parentheses
x+14x-(-5x+128)-35+3=0
We get rid of parentheses
x+14x+5x-128-35+3=0
We add all the numbers together, and all the variables
20x-160=0
We move all terms containing x to the left, all other terms to the right
20x=160
x=160/20
x=8
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