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3+7/8x=1/2x
We move all terms to the left:
3+7/8x-(1/2x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/8x-(+1/2x)+3=0
We get rid of parentheses
7/8x-1/2x+3=0
We calculate fractions
14x/16x^2+(-8x)/16x^2+3=0
We multiply all the terms by the denominator
14x+(-8x)+3*16x^2=0
Wy multiply elements
48x^2+14x+(-8x)=0
We get rid of parentheses
48x^2+14x-8x=0
We add all the numbers together, and all the variables
48x^2+6x=0
a = 48; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·48·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*48}=\frac{-12}{96} =-1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*48}=\frac{0}{96} =0 $
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