3+9(x-3)=9-4(x-2)

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Solution for 3+9(x-3)=9-4(x-2) equation: 



3+9(x-3)=9-4(x-2)

We move all terms to the left:

3+9(x-3)-(9-4(x-2))=0

We multiply parentheses

9x-(9-4(x-2))-27+3=0



We calculate terms in parentheses: -(9-4(x-2)), so:

9-4(x-2)

determiningTheFunctionDomain
-4(x-2)+9

We multiply parentheses

-4x+8+9

We add all the numbers together, and all the variables

-4x+17

Back to the equation:

-(-4x+17)



We add all the numbers together, and all the variables

9x-(-4x+17)-24=0

We get rid of parentheses

9x+4x-17-24=0

We add all the numbers together, and all the variables

13x-41=0

We move all terms containing x to the left, all other terms to the right

13x=41

x=41/13

x=3+2/13

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