3+f=2(2f-1)

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Solution for 3+f=2(2f-1) equation: 



3+f=2(2f-1)

We move all terms to the left:

3+f-(2(2f-1))=0



We calculate terms in parentheses: -(2(2f-1)), so:

2(2f-1)

We multiply parentheses

4f-2

Back to the equation:

-(4f-2)



We get rid of parentheses

f-4f+2+3=0

We add all the numbers together, and all the variables

-3f+5=0

We move all terms containing f to the left, all other terms to the right

-3f=-5

f=-5/-3

f=1+2/3

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