3+w/6w=1/2w+4/3

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Solution for 3+w/6w=1/2w+4/3 equation:


w in (-oo:+oo)

(w/6)*w+3 = (1/2)*w+4/3 // - (1/2)*w+4/3

(w/6)*w-((1/2)*w)-(4/3)+3 = 0

(w/6)*w+(-1/2)*w-4/3+3 = 0

1/6*w^2-1/2*w+5/3 = 0

DELTA = (-1/2)^2-(1/6*5/3*4)

DELTA = -31/36

DELTA < 0

w belongs to the empty set

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