3+x=(19+x)/2

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Solution for 3+x=(19+x)/2 equation: 



3+x=(19+x)/2

We move all terms to the left:

3+x-((19+x)/2)=0

We add all the numbers together, and all the variables

x-((x+19)/2)+3=0

We multiply all the terms by the denominator


x*2)-((x+19)+3*2)=0

We add all the numbers together, and all the variables

x*2)-((x+19)=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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