3+y=(8/y)-y

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Solution for 3+y=(8/y)-y equation: 



3+y=(8/y)-y

We move all terms to the left:

3+y-((8/y)-y)=0



Domain of the equation: y)-y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

y-((+8/y)-y)+3=0

We multiply all the terms by the denominator


y*y)-y)-((+3*y)-y)+8=0

We add all the numbers together, and all the variables

y*y)-y)-((+3y)-y)+8=0

Wy multiply elements

y^2+3y)-y)+8=0

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