3+z=2(2z-1)

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Solution for 3+z=2(2z-1) equation: 



3+z=2(2z-1)

We move all terms to the left:

3+z-(2(2z-1))=0



We calculate terms in parentheses: -(2(2z-1)), so:

2(2z-1)

We multiply parentheses

4z-2

Back to the equation:

-(4z-2)



We get rid of parentheses

z-4z+2+3=0

We add all the numbers together, and all the variables

-3z+5=0

We move all terms containing z to the left, all other terms to the right

-3z=-5

z=-5/-3

z=1+2/3

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