3,010=43p(p+25)

Solution for 3,010=43p(p+25) equation:

3.010=43p(p+25)

We move all terms to the left:

3.010-(43p(p+25))=0

We add all the numbers together, and all the variables

-(43p(p+25))+3.01=0


We calculate terms in parentheses: -(43p(p+25)), so:

43p(p+25)

We multiply parentheses

43p^2+1075p

Back to the equation:

-(43p^2+1075p)


We get rid of parentheses

-43p^2-1075p+3.01=0

a = -43; b = -1075; c = +3.01;
Δ = b2-4ac
Δ = -10752-4·(-43)·3.01
Δ = 1156142.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1075)-\sqrt{1156142.72}}{2*-43}=\frac{1075-\sqrt{1156142.72}}{-86}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1075)+\sqrt{1156142.72}}{2*-43}=\frac{1075+\sqrt{1156142.72}}{-86}
$