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3.75y+18+5.3/4y=6.5y+30
We move all terms to the left:
3.75y+18+5.3/4y-(6.5y+30)=0
Domain of the equation: 4y!=0We get rid of parentheses
y!=0/4
y!=0
y∈R
3.75y+5.3/4y-6.5y-30+18=0
We multiply all the terms by the denominator
(3.75y)*4y-(6.5y)*4y-30*4y+18*4y+5.3=0
We add all the numbers together, and all the variables
(+3.75y)*4y-(+6.5y)*4y-30*4y+18*4y+5.3=0
We multiply parentheses
12y^2-24y^2-30*4y+18*4y+5.3=0
Wy multiply elements
12y^2-24y^2-120y+72y+5.3=0
We add all the numbers together, and all the variables
-12y^2-48y+5.3=0
a = -12; b = -48; c = +5.3;
Δ = b2-4ac
Δ = -482-4·(-12)·5.3
Δ = 2558.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-\sqrt{2558.4}}{2*-12}=\frac{48-\sqrt{2558.4}}{-24} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+\sqrt{2558.4}}{2*-12}=\frac{48+\sqrt{2558.4}}{-24} $
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