3-(-1a)=4a+12

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Solution for 3-(-1a)=4a+12 equation: 



3-(-1a)=4a+12

We move all terms to the left:

3-(-1a)-(4a+12)=0

We get rid of parentheses

1a-4a-12+3=0

We add all the numbers together, and all the variables

-3a-9=0

We move all terms containing a to the left, all other terms to the right

-3a=9

a=9/-3

a=-3

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