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3-(1)/(2)x+5-(4)/(3)x=-2
We move all terms to the left:
3-(1)/(2)x+5-(4)/(3)x-(-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1/2x-4/3x+10=0
We calculate fractions
(-3x)/6x^2+(-8x)/6x^2+10=0
We multiply all the terms by the denominator
(-3x)+(-8x)+10*6x^2=0
Wy multiply elements
60x^2+(-3x)+(-8x)=0
We get rid of parentheses
60x^2-3x-8x=0
We add all the numbers together, and all the variables
60x^2-11x=0
a = 60; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·60·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*60}=\frac{0}{120} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*60}=\frac{22}{120} =11/60 $
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