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3-(1/7x-10)=2/5(x+15)
We move all terms to the left:
3-(1/7x-10)-(2/5(x+15))=0
Domain of the equation: 7x-10)!=0
x∈R
Domain of the equation: 5(x+15))!=0We get rid of parentheses
x∈R
-1/7x-(2/5(x+15))+10+3=0
We calculate fractions
(-5xx/(35x^2x+(-(2*7x)/(35x^2x+10+3=0
We can not solve this equation
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