3-(2-3x)=4(x-2)+5

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Solution for 3-(2-3x)=4(x-2)+5 equation: 



3-(2-3x)=4(x-2)+5

We move all terms to the left:

3-(2-3x)-(4(x-2)+5)=0

We add all the numbers together, and all the variables

-(-3x+2)-(4(x-2)+5)+3=0

We get rid of parentheses

3x-(4(x-2)+5)-2+3=0



We calculate terms in parentheses: -(4(x-2)+5), so:

4(x-2)+5

We multiply parentheses

4x-8+5

We add all the numbers together, and all the variables

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

3x-(4x-3)+1=0

We get rid of parentheses

3x-4x+3+1=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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