3-(22/x+5)=(6x-1)/(2x+7)

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Solution for 3-(22/x+5)=(6x-1)/(2x+7) equation: 


D( x )

x = 0

2*x+7 = 0

x = 0

x = 0

2*x+7 = 0

2*x+7 = 0

2*x+7 = 0 // - 7

2*x = -7 // : 2

x = -7/2

x in (-oo:-7/2) U (-7/2:0) U (0:+oo)

3-(22/x)-5 = (6*x-1)/(2*x+7) // - (6*x-1)/(2*x+7)

3-((6*x-1)/(2*x+7))-(22/x)-5 = 0

3-((6*x-1)/(2*x+7))-22*x^-1-5 = 0

(-1*(6*x-1))/(2*x+7)-22/x-5+3 = 0

(-1*x*(6*x-1))/(x*(2*x+7))+(-22*(2*x+7))/(x*(2*x+7))+(-5*x*(2*x+7))/(x*(2*x+7))+(3*x*(2*x+7))/(x*(2*x+7)) = 0

3*x*(2*x+7)-1*x*(6*x-1)-22*(2*x+7)-5*x*(2*x+7) = 0

6*x^2-6*x^2-10*x^2-43*x-35*x+21*x-154 = 0

6*x^2-16*x^2-78*x+21*x-154 = 0

-10*x^2-57*x-154 = 0

-10*x^2-57*x-154 = 0

-1*(10*x^2+57*x+154) = 0

10*x^2+57*x+154 = 0

DELTA = 57^2-(4*10*154)

DELTA = -2911

DELTA < 0

-1 = 0

-1/(x*(2*x+7)) = 0

-1/(x*(2*x+7)) = 0 // * x*(2*x+7)

-1 = 0

x belongs to the empty set

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