3-(27/x)=(x/3)-5

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Solution for 3-(27/x)=(x/3)-5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3-(27/x) = x/3-5 // - x/3-5

3-(x/3)-(27/x)+5 = 0

3-(x/3)-27*x^-1+5 = 0

8*x^0-1/3*x^1-27*x^-1 = 0

(8*x^1-1/3*x^2-27*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^1-1/3*x^2-27*x^0) = 0

x^1

(-1/3)*x^2+8*x-27 = 0

(-1/3)*x^2+8*x-27 = 0

DELTA = 8^2-(-27*4*(-1/3))

DELTA = 28

DELTA > 0

x = (28^(1/2)-8)/(2*(-1/3)) or x = (-28^(1/2)-8)/(2*(-1/3))

x = -3/2*(2*7^(1/2)-8) or x = -3/2*(-2*7^(1/2)-8)

x in { -3/2*(2*7^(1/2)-8), -3/2*(-2*7^(1/2)-8)}

x in { -3/2*(2*7^(1/2)-8), -3/2*(-2*7^(1/2)-8) }

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