3-(2p-4)=14+2(p+3p)-3p

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Solution for 3-(2p-4)=14+2(p+3p)-3p equation:



3-(2p-4)=14+2(p+3p)-3p
We move all terms to the left:
3-(2p-4)-(14+2(p+3p)-3p)=0
We add all the numbers together, and all the variables
-(2p-4)-(14+2(+4p)-3p)+3=0
We get rid of parentheses
-2p-(14+2(+4p)-3p)+4+3=0
We calculate terms in parentheses: -(14+2(+4p)-3p), so:
14+2(+4p)-3p
determiningTheFunctionDomain 2(+4p)-3p+14
We add all the numbers together, and all the variables
-3p+2(+4p)+14
We multiply parentheses
-3p+8p+14
We add all the numbers together, and all the variables
5p+14
Back to the equation:
-(5p+14)
We add all the numbers together, and all the variables
-2p-(5p+14)+7=0
We get rid of parentheses
-2p-5p-14+7=0
We add all the numbers together, and all the variables
-7p-7=0
We move all terms containing p to the left, all other terms to the right
-7p=7
p=7/-7
p=-1

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