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3-(2x+5)=-2(2x-5)+5x
We move all terms to the left:
3-(2x+5)-(-2(2x-5)+5x)=0
We get rid of parentheses
-2x-(-2(2x-5)+5x)-5+3=0
We calculate terms in parentheses: -(-2(2x-5)+5x), so:We add all the numbers together, and all the variables
-2(2x-5)+5x
We add all the numbers together, and all the variables
5x-2(2x-5)
We multiply parentheses
5x-4x+10
We add all the numbers together, and all the variables
x+10
Back to the equation:
-(x+10)
-2x-(x+10)-2=0
We get rid of parentheses
-2x-x-10-2=0
We add all the numbers together, and all the variables
-3x-12=0
We move all terms containing x to the left, all other terms to the right
-3x=12
x=12/-3
x=-4
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