3-(2x-3)=2(3x-2)

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Solution for 3-(2x-3)=2(3x-2) equation: 



3-(2x-3)=2(3x-2)

We move all terms to the left:

3-(2x-3)-(2(3x-2))=0

We get rid of parentheses

-2x-(2(3x-2))+3+3=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

-2x-(6x-4)+6=0

We get rid of parentheses

-2x-6x+4+6=0

We add all the numbers together, and all the variables

-8x+10=0

We move all terms containing x to the left, all other terms to the right

-8x=-10

x=-10/-8

x=1+1/4

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