3-(2x-5)=56x+(12+7x)-9

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Solution for 3-(2x-5)=56x+(12+7x)-9 equation: 



3-(2x-5)=56x+(12+7x)-9

We move all terms to the left:

3-(2x-5)-(56x+(12+7x)-9)=0

We add all the numbers together, and all the variables

-(2x-5)-(56x+(7x+12)-9)+3=0

We get rid of parentheses

-2x-(56x+(7x+12)-9)+5+3=0



We calculate terms in parentheses: -(56x+(7x+12)-9), so:

56x+(7x+12)-9

We get rid of parentheses

56x+7x+12-9

We add all the numbers together, and all the variables

63x+3

Back to the equation:

-(63x+3)



We add all the numbers together, and all the variables

-2x-(63x+3)+8=0

We get rid of parentheses

-2x-63x-3+8=0

We add all the numbers together, and all the variables

-65x+5=0

We move all terms containing x to the left, all other terms to the right

-65x=-5

x=-5/-65

x=1/13

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