3-(2x-9)=1/3(-6x+27)+3

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Solution for 3-(2x-9)=1/3(-6x+27)+3 equation:



3-(2x-9)=1/3(-6x+27)+3
We move all terms to the left:
3-(2x-9)-(1/3(-6x+27)+3)=0
Domain of the equation: 3(-6x+27)+3)!=0
x∈R
We get rid of parentheses
-2x-(1/3(-6x+27)+3)+9+3=0
We multiply all the terms by the denominator
-2x*3(-6x+27)+9*3(-6x+27)-6x+3)-(1+3)+3*3(+27)+3)=0
We add all the numbers together, and all the variables
-2x*3(-6x+27)+9*3(-6x+27)-6x+3)-4+3*327+3)=0
We add all the numbers together, and all the variables
-6x-2x*3(-6x+27)+9*3(-6x+27)=0
Wy multiply elements
-6x^2(-+27x(--6x=0
We use the square of the difference formula
-6x^2(-27x(+6x=0

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