3-(3*x)=23-(x/2)

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Solution for 3-(3*x)=23-(x/2) equation:



3-(3*x)=23-(x/2)
We move all terms to the left:
3-(3*x)-(23-(x/2))=0
We add all the numbers together, and all the variables
-(+3x)-(23-(+x/2))+3=0
We get rid of parentheses
-3x-(23-(+x/2))+3=0
We multiply all the terms by the denominator
-3x*2))-(23-(+x+3*2))=0
We add all the numbers together, and all the variables
-3x*2))-(23-(x+6))=0
We add all the numbers together, and all the variables
-3x*2))-(23-(x=0
Wy multiply elements
-6x^2=0
a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$

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