3-(3x+50)=2(-1+x)+(x-5)

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Solution for 3-(3x+50)=2(-1+x)+(x-5) equation: 



3-(3x+50)=2(-1+x)+(x-5)

We move all terms to the left:

3-(3x+50)-(2(-1+x)+(x-5))=0

We add all the numbers together, and all the variables

-(3x+50)-(2(x-1)+(x-5))+3=0

We get rid of parentheses

-3x-(2(x-1)+(x-5))-50+3=0



We calculate terms in parentheses: -(2(x-1)+(x-5)), so:

2(x-1)+(x-5)

We multiply parentheses

2x+(x-5)-2

We get rid of parentheses

2x+x-5-2

We add all the numbers together, and all the variables

3x-7

Back to the equation:

-(3x-7)



We add all the numbers together, and all the variables

-3x-(3x-7)-47=0

We get rid of parentheses

-3x-3x+7-47=0

We add all the numbers together, and all the variables

-6x-40=0

We move all terms containing x to the left, all other terms to the right

-6x=40

x=40/-6

x=-6+2/3

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