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3-(3x-2)-(x+12)=4x
We move all terms to the left:
3-(3x-2)-(x+12)-(4x)=0
We add all the numbers together, and all the variables
-4x-(3x-2)-(x+12)+3=0
We get rid of parentheses
-4x-3x-x+2-12+3=0
We add all the numbers together, and all the variables
-8x-7=0
We move all terms containing x to the left, all other terms to the right
-8x=7
x=7/-8
x=-7/8
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