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3-(3x-5)=6x+2(4+8x)
We move all terms to the left:
3-(3x-5)-(6x+2(4+8x))=0
We add all the numbers together, and all the variables
-(3x-5)-(6x+2(8x+4))+3=0
We get rid of parentheses
-3x-(6x+2(8x+4))+5+3=0
We calculate terms in parentheses: -(6x+2(8x+4)), so:We add all the numbers together, and all the variables
6x+2(8x+4)
We multiply parentheses
6x+16x+8
We add all the numbers together, and all the variables
22x+8
Back to the equation:
-(22x+8)
-3x-(22x+8)+8=0
We get rid of parentheses
-3x-22x-8+8=0
We add all the numbers together, and all the variables
-25x=0
x=0/-25
x=0
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