3-(41-4x)=4x+19(2x-22)

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Solution for 3-(41-4x)=4x+19(2x-22) equation: 



3-(41-4x)=4x+19(2x-22)

We move all terms to the left:

3-(41-4x)-(4x+19(2x-22))=0

We add all the numbers together, and all the variables

-(-4x+41)-(4x+19(2x-22))+3=0

We get rid of parentheses

4x-(4x+19(2x-22))-41+3=0



We calculate terms in parentheses: -(4x+19(2x-22)), so:

4x+19(2x-22)

We multiply parentheses

4x+38x-418

We add all the numbers together, and all the variables

42x-418

Back to the equation:

-(42x-418)



We add all the numbers together, and all the variables

4x-(42x-418)-38=0

We get rid of parentheses

4x-42x+418-38=0

We add all the numbers together, and all the variables

-38x+380=0

We move all terms containing x to the left, all other terms to the right

-38x=-380

x=-380/-38

x=+10

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