3-(4m+2)=m-9(m-2m)+3

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Solution for 3-(4m+2)=m-9(m-2m)+3 equation: 



3-(4m+2)=m-9(m-2m)+3

We move all terms to the left:

3-(4m+2)-(m-9(m-2m)+3)=0

We add all the numbers together, and all the variables

-(4m+2)-(m-9(-1m)+3)+3=0

We get rid of parentheses

-4m-(m-9(-1m)+3)-2+3=0



We calculate terms in parentheses: -(m-9(-1m)+3), so:

m-9(-1m)+3

We multiply parentheses

m+9m+3

We add all the numbers together, and all the variables

10m+3

Back to the equation:

-(10m+3)



We add all the numbers together, and all the variables

-4m-(10m+3)+1=0

We get rid of parentheses

-4m-10m-3+1=0

We add all the numbers together, and all the variables

-14m-2=0

We move all terms containing m to the left, all other terms to the right

-14m=2

m=2/-14

m=-1/7

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