3-(4w+5)=1/2(8w+28

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Solution for 3-(4w+5)=1/2(8w+28 equation: 



3-(4w+5)=1/2(8w+28

We move all terms to the left:

3-(4w+5)-(1/2(8w+28)=0



Domain of the equation: 2(8w+28)+3!=0

We move all terms containing w to the left, all other terms to the right

2(8w+28)!=-3

w∈R



We get rid of parentheses

-4w-(1/2(8w+28)+3-5=0

We multiply all the terms by the denominator


-4w*2(8w+28)+3-5-(1=0

We add all the numbers together, and all the variables

-4w*2(8w+28)=0

Wy multiply elements

-8w^2(8=0

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