3-(4w+5)=1/3(8w+28)

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Solution for 3-(4w+5)=1/3(8w+28) equation: 



3-(4w+5)=1/3(8w+28)

We move all terms to the left:

3-(4w+5)-(1/3(8w+28))=0



Domain of the equation: 3(8w+28))!=0

w∈R



We get rid of parentheses

-4w-(1/3(8w+28))-5+3=0

We multiply all the terms by the denominator


-4w*3(8w+28))-(1-5*3(8w+28))+3*3(8w+28))=0

We add all the numbers together, and all the variables

-4w*3(8w+28))-(1-5*3(8w+28))+3*3(8w=0

Wy multiply elements

-12w^2(8-45w^2(8=0

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