3-(4w+5)=12(8w+28)

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Solution for 3-(4w+5)=12(8w+28) equation: 



3-(4w+5)=12(8w+28)

We move all terms to the left:

3-(4w+5)-(12(8w+28))=0

We get rid of parentheses

-4w-(12(8w+28))-5+3=0



We calculate terms in parentheses: -(12(8w+28)), so:

12(8w+28)

We multiply parentheses

96w+336

Back to the equation:

-(96w+336)



We add all the numbers together, and all the variables

-4w-(96w+336)-2=0

We get rid of parentheses

-4w-96w-336-2=0

We add all the numbers together, and all the variables

-100w-338=0

We move all terms containing w to the left, all other terms to the right

-100w=338

w=338/-100

w=-3+19/50

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