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3-(4w+50=1/2(8w+28
We move all terms to the left:
3-(4w+50-(1/2(8w+28)=0
Domain of the equation: 2(8w+28)+3!=0We multiply all the terms by the denominator
We move all terms containing w to the left, all other terms to the right
2(8w+28)!=-3
w∈R
-(4w+50-(1=0
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