3-(4x-20)=5(x-3)

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Solution for 3-(4x-20)=5(x-3) equation: 



3-(4x-20)=5(x-3)

We move all terms to the left:

3-(4x-20)-(5(x-3))=0

We get rid of parentheses

-4x-(5(x-3))+20+3=0



We calculate terms in parentheses: -(5(x-3)), so:

5(x-3)

We multiply parentheses

5x-15

Back to the equation:

-(5x-15)



We add all the numbers together, and all the variables

-4x-(5x-15)+23=0

We get rid of parentheses

-4x-5x+15+23=0

We add all the numbers together, and all the variables

-9x+38=0

We move all terms containing x to the left, all other terms to the right

-9x=-38

x=-38/-9

x=4+2/9

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