3-(5y+2(y-1)+4)=5-(2(y-3)-3(y-2))

Solution for 3-(5y+2(y-1)+4)=5-(2(y-3)-3(y-2)) equation:

3-(5y+2(y-1)+4)=5-(2(y-3)-3(y-2))

We move all terms to the left:

3-(5y+2(y-1)+4)-(5-(2(y-3)-3(y-2)))=0


We calculate terms in parentheses: -(5y+2(y-1)+4), so:

5y+2(y-1)+4

We multiply parentheses

5y+2y-2+4

We add all the numbers together, and all the variables

7y+2

Back to the equation:

-(7y+2)



We calculate terms in parentheses: -(5-(2(y-3)-3(y-2))), so:

5-(2(y-3)-3(y-2))

determiningTheFunctionDomain
-(2(y-3)-3(y-2))+5


We calculate terms in parentheses: -(2(y-3)-3(y-2)), so:

2(y-3)-3(y-2)

We multiply parentheses

2y-3y-6+6

We add all the numbers together, and all the variables

-y

Back to the equation:

-(-y)


We add all the numbers together, and all the variables

-(-1y)+5

We get rid of parentheses

1y+5

We add all the numbers together, and all the variables

y+5

Back to the equation:

-(y+5)


We get rid of parentheses

-7y-y-2-5+3=0

We add all the numbers together, and all the variables

-8y-4=0

We move all terms containing y to the left, all other terms to the right

-8y=4

y=4/-8

y=-1/2