3-(5z+24)+2=2(3-2z)-4

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Solution for 3-(5z+24)+2=2(3-2z)-4 equation: 



3-(5z+24)+2=2(3-2z)-4

We move all terms to the left:

3-(5z+24)+2-(2(3-2z)-4)=0

We add all the numbers together, and all the variables

-(5z+24)-(2(-2z+3)-4)+3+2=0

We add all the numbers together, and all the variables

-(5z+24)-(2(-2z+3)-4)+5=0

We get rid of parentheses

-5z-(2(-2z+3)-4)-24+5=0



We calculate terms in parentheses: -(2(-2z+3)-4), so:

2(-2z+3)-4

We multiply parentheses

-4z+6-4

We add all the numbers together, and all the variables

-4z+2

Back to the equation:

-(-4z+2)



We add all the numbers together, and all the variables

-5z-(-4z+2)-19=0

We get rid of parentheses

-5z+4z-2-19=0

We add all the numbers together, and all the variables

-1z-21=0

We move all terms containing z to the left, all other terms to the right

-z=21

z=21/-1

z=-21

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