3-(8v-5)+(6-7v)-1=7-(v-1)+(4v-4)

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Solution for 3-(8v-5)+(6-7v)-1=7-(v-1)+(4v-4) equation: 



3-(8v-5)+(6-7v)-1=7-(v-1)+(4v-4)

We move all terms to the left:

3-(8v-5)+(6-7v)-1-(7-(v-1)+(4v-4))=0

We add all the numbers together, and all the variables

-(8v-5)+(-7v+6)-(7-(v-1)+(4v-4))+3-1=0

We add all the numbers together, and all the variables

-(8v-5)+(-7v+6)-(7-(v-1)+(4v-4))+2=0

We get rid of parentheses

-8v-7v-(7-(v-1)+(4v-4))+5+6+2=0



We calculate terms in parentheses: -(7-(v-1)+(4v-4)), so:

7-(v-1)+(4v-4)

determiningTheFunctionDomain
-(v-1)+(4v-4)+7

We get rid of parentheses

-v+4v+1-4+7

We add all the numbers together, and all the variables

3v+4

Back to the equation:

-(3v+4)



We add all the numbers together, and all the variables

-15v-(3v+4)+13=0

We get rid of parentheses

-15v-3v-4+13=0

We add all the numbers together, and all the variables

-18v+9=0

We move all terms containing v to the left, all other terms to the right

-18v=-9

v=-9/-18

v=1/2

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