3-(8x-7)+18x=31x-2(45+14x)-47

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Solution for 3-(8x-7)+18x=31x-2(45+14x)-47 equation: 



3-(8x-7)+18x=31x-2(45+14x)-47

We move all terms to the left:

3-(8x-7)+18x-(31x-2(45+14x)-47)=0

We add all the numbers together, and all the variables

-(8x-7)+18x-(31x-2(14x+45)-47)+3=0

We add all the numbers together, and all the variables

18x-(8x-7)-(31x-2(14x+45)-47)+3=0

We get rid of parentheses

18x-8x-(31x-2(14x+45)-47)+7+3=0



We calculate terms in parentheses: -(31x-2(14x+45)-47), so:

31x-2(14x+45)-47

We multiply parentheses

31x-28x-90-47

We add all the numbers together, and all the variables

3x-137

Back to the equation:

-(3x-137)



We add all the numbers together, and all the variables

10x-(3x-137)+10=0

We get rid of parentheses

10x-3x+137+10=0

We add all the numbers together, and all the variables

7x+147=0

We move all terms containing x to the left, all other terms to the right

7x=-147

x=-147/7

x=-21

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