3-(8z-5)+(6-7z)-1=7-(z-1)+4(2+1)

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Solution for 3-(8z-5)+(6-7z)-1=7-(z-1)+4(2+1) equation: 



3-(8z-5)+(6-7z)-1=7-(z-1)+4(2+1)

We move all terms to the left:

3-(8z-5)+(6-7z)-1-(7-(z-1)+4(2+1))=0

We add all the numbers together, and all the variables

-(8z-5)+(-7z+6)-(7-(z-1)+43)+3-1=0

We add all the numbers together, and all the variables

-(8z-5)+(-7z+6)-(7-(z-1)+43)+2=0

We get rid of parentheses

-8z-7z-(7-(z-1)+43)+5+6+2=0



We calculate terms in parentheses: -(7-(z-1)+43), so:

7-(z-1)+43

determiningTheFunctionDomain
-(z-1)+7+43

We add all the numbers together, and all the variables

-(z-1)+50

We get rid of parentheses

-z+1+50

We add all the numbers together, and all the variables

-1z+51

Back to the equation:

-(-1z+51)



We add all the numbers together, and all the variables

-15z-(-1z+51)+13=0

We get rid of parentheses

-15z+1z-51+13=0

We add all the numbers together, and all the variables

-14z-38=0

We move all terms containing z to the left, all other terms to the right

-14z=38

z=38/-14

z=-2+5/7

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