3-(b-2)=3

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Solution for 3-(b-2)=3 equation: 



3-(b-2)=3

We move all terms to the left:

3-(b-2)-(3)=0

We add all the numbers together, and all the variables

-(b-2)=0

We get rid of parentheses

-b+2=0

We add all the numbers together, and all the variables

-1b+2=0

We move all terms containing b to the left, all other terms to the right

-b=-2

b=-2/-1

b=+2

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