3-(c+5)=4(2c+1)+1

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Solution for 3-(c+5)=4(2c+1)+1 equation: 



3-(c+5)=4(2c+1)+1

We move all terms to the left:

3-(c+5)-(4(2c+1)+1)=0

We get rid of parentheses

-c-(4(2c+1)+1)-5+3=0



We calculate terms in parentheses: -(4(2c+1)+1), so:

4(2c+1)+1

We multiply parentheses

8c+4+1

We add all the numbers together, and all the variables

8c+5

Back to the equation:

-(8c+5)



We add all the numbers together, and all the variables

-1c-(8c+5)-2=0

We get rid of parentheses

-1c-8c-5-2=0

We add all the numbers together, and all the variables

-9c-7=0

We move all terms containing c to the left, all other terms to the right

-9c=7

c=7/-9

c=-7/9

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