3-(n+2)=-14-7n

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Solution for 3-(n+2)=-14-7n equation: 



3-(n+2)=-14-7n

We move all terms to the left:

3-(n+2)-(-14-7n)=0

We add all the numbers together, and all the variables

-(n+2)-(-7n-14)+3=0

We get rid of parentheses

-n+7n-2+14+3=0

We add all the numbers together, and all the variables

6n+15=0

We move all terms containing n to the left, all other terms to the right

6n=-15

n=-15/6

n=-2+1/2

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