3-(n+2)=n-22

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Solution for 3-(n+2)=n-22 equation: 



3-(n+2)=n-22

We move all terms to the left:

3-(n+2)-(n-22)=0

We get rid of parentheses

-n-n-2+22+3=0

We add all the numbers together, and all the variables

-2n+23=0

We move all terms containing n to the left, all other terms to the right

-2n=-23

n=-23/-2

n=11+1/2

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