3-(n-1)=1/2(3n-4)

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Solution for 3-(n-1)=1/2(3n-4) equation: 



3-(n-1)=1/2(3n-4)

We move all terms to the left:

3-(n-1)-(1/2(3n-4))=0



Domain of the equation: 2(3n-4))!=0

n∈R



We get rid of parentheses

-n-(1/2(3n-4))+1+3=0

We multiply all the terms by the denominator


-n*2(3n-4))-(1+1*2(3n-4))+3*2(3n-4))=0

We add all the numbers together, and all the variables

-n*2(3n-4))-(1+1*2(3n-4))+3*2(3n=0

Wy multiply elements

-2n^2(3+4n^2(3=0

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